15β2/β270 * β270/β270 15β540/270 = 15*6β15/270 = β15/3
or
15β2/β270 = 15/β135 = 15/3β15 = 5/β15 * β15/β15 = 5β15/15 = β15/3
Simplify by rationalizing the denominator ....15 sqrt 2/ sqrt 270
or
15β2/β270 = 15/β135 = 15/3β15 = 5/β15 * β15/β15 = 5β15/15 = β15/3
Here are the step-by-step instructions:
Step 1: Simplify the numerator if possible. In this case, the numerator is already simplified as 15β2.
Step 2: Simplify the denominator if possible. Here, we have the square root of 270. To simplify it, we can find the perfect squares that are factors of 270. We see that 270 can be written as 9 * 30, and 9 is a perfect square (3 * 3). So, the square root of 270 can be simplified to 3β30.
Step 3: Now, we have the expression as (15β2) / (3β30).
Step 4: To rationalize the denominator, we multiply both the numerator and denominator by the conjugate of the denominator. The conjugate is found by changing the sign of the middle term in the denominator.
In this case, the conjugate of 3β30 is -3β30.
Step 5: Multiply the numerator and denominator by the conjugate. We get:
((15β2) / (3β30)) * ((-3β30) / (-3β30))
Simplifying this expression, we get:
(-45β2β30) / (-9 * 30)
Here, β2 * β30 = β(2 * 30) = β60 = 2β15.
So, the expression becomes:
(-45 * 2β15) / (-270)
Simplifying further:
(-90β15) / (-270)
Step 6: Simplify the negative signs. Since we have a negative divided by a negative, they cancel each other out, so the expression becomes:
90β15 / 270
Step 7: Divide the numerator and denominator by their greatest common factor, which is 90 in this case. We get:
β15 / 3
Therefore, the simplified expression after rationalizing the denominator is β15 / 3.