Asked by Shiro
Can anyone help me?
Ksp of CuCO3 = 3.5x10^ -4
Ksp of Ca(OH)2 = 8.9x10^ -5
Ksp of Ag2CrO4 = 10.0x10^-11.
Given by these, Which has the highest molar solubility? Thanks
Ksp of CuCO3 = 3.5x10^ -4
Ksp of Ca(OH)2 = 8.9x10^ -5
Ksp of Ag2CrO4 = 10.0x10^-11.
Given by these, Which has the highest molar solubility? Thanks
Answers
Answered by
DrBob222
Determine the solubility of each using Ksp then compare the numbers. Pick the largest number. Here is how you do Ag2CrO4.
..............Ag2CrO4 ==> 2Ag^+ + CrO4^2-
I..............solid.................0...............0
C.............solid................2x..............x
E..............solid...............2x...............x
Ksp = (Ag^+)^2(CrO4)
Substitute the E line into Ksp expression and solve for x = solubility of Ag2CrO4 in moles/L.
Ksp = (2x)^2 (x)
..............Ag2CrO4 ==> 2Ag^+ + CrO4^2-
I..............solid.................0...............0
C.............solid................2x..............x
E..............solid...............2x...............x
Ksp = (Ag^+)^2(CrO4)
Substitute the E line into Ksp expression and solve for x = solubility of Ag2CrO4 in moles/L.
Ksp = (2x)^2 (x)
Answered by
Claire
Thank youuuu. :D