Question

Can anyone help me?
Ksp of CuCO3 = 3.5x10^ -4
Ksp of Ca(OH)2 = 8.9x10^ -5
Ksp of Ag2CrO4 = 10.0x10^-11.
Given by these, Which has the highest molar solubility? Thanks

Answer 1

Determine the solubility of each using Ksp then compare the numbers. Pick the largest number. Here is how you do Ag2CrO4.
..............Ag2CrO4 ==> 2Ag^+ + CrO4^2-
I..............solid.................0...............0
C.............solid................2x..............x
E..............solid...............2x...............x
Ksp = (Ag^+)^2(CrO4)
Substitute the E line into Ksp expression and solve for x = solubility of Ag2CrO4 in moles/L.
Ksp = (2x)^2 (x)

Answer 2

Thank youuuu. :D