Asked by Hermela
r=6+3sin(theta) convert to rectangular coordinates
Answers
Answered by
oobleck
r = 6 + 3sinθ
r^2 = 6r + 3rsinθ
x^2+y^2 = 6√(x^2+y^2) + 3y
x^2 + y^2 - 3y = 6√(x^2+y^2)
(x^2+y^2-3y)^2 = 36(x^2+y^2)
r^2 = 6r + 3rsinθ
x^2+y^2 = 6√(x^2+y^2) + 3y
x^2 + y^2 - 3y = 6√(x^2+y^2)
(x^2+y^2-3y)^2 = 36(x^2+y^2)
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