Asked by person
A jeweler has three solid gold cylinders with radii 2.0 millimeters, 3.0 millimeters, and 4.0 millimeters. Each cylinder
has a height of 10.0 millimeters. If the jeweler melts the cylinders down to make a solid prism with a square base of
length 5.0 millimeters, what will be the approximate height of the prism? Round to the nearest tenth.
has a height of 10.0 millimeters. If the jeweler melts the cylinders down to make a solid prism with a square base of
length 5.0 millimeters, what will be the approximate height of the prism? Round to the nearest tenth.
Answers
Answered by
oobleck
the total volumes of the cylinders must equal the volume of the prism, so
π(2^2 + 3^2 + 4^2)*10 = 5^2 * h
π(2^2 + 3^2 + 4^2)*10 = 5^2 * h
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