Asked by Ana
Liquid water boils at 100 degrees C. In other words, this is the temperature at which the thermal energy between two molecules of water overcomes the interaction energy. Given this, what is the interaction energy (Uint) of liquid water?
3/2*(1.38*10e-23)*373.15= 7.7e-20
3/2*(1.38*10e-23)*373.15= 7.7e-20
Answers
Answered by
Ana
7.72*10-21J
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.