Question
Convert x+2y=5 to polar form
Answers
Reiny
recall:
cosØ = x/r ---> x = rcosØ
sinØ = y/r ---> y = rsinØ
x+2y=5
rcosØ + 2rsinØ = 5
confirm
https://www.wolframalpha.com/input/?i=polar+graph+rcos%CE%B8+%2B+2rsin%CE%B8+%3D+5
cosØ = x/r ---> x = rcosØ
sinØ = y/r ---> y = rsinØ
x+2y=5
rcosØ + 2rsinØ = 5
confirm
https://www.wolframalpha.com/input/?i=polar+graph+rcos%CE%B8+%2B+2rsin%CE%B8+%3D+5
Bosnian
x = r cos θ
y = r sin θ
x + 2 y = 5
becomes
r cos θ + 2 r sin θ = 5
r ( cos θ + 2 sin θ ) = 5
r = 5 / ( cos θ + 2 sin θ )
y = r sin θ
x + 2 y = 5
becomes
r cos θ + 2 r sin θ = 5
r ( cos θ + 2 sin θ ) = 5
r = 5 / ( cos θ + 2 sin θ )