Asked by help!
A new potential heart medicine, code-named X-281, is being tested by a pharmaceutical company, Pharma-pill. As a research technician at Pharma-pill, you are told that X-281 is a monoprotic weak acid, but because of security concerns, the actual chemical formula must remain top secret. The company is interested in the drug's value because only the dissociated form of the chemical is active in preventing cholesterol buildup in arteries. To find the of X-281, you prepare a 0.079 test solution of X-281. The pH of the solution is determined to be 3.00. What is the of X-281?
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Answered by
DrBob222
You need to re-read your post an fill in the missing blanks. For example, two lines from the bottom:
To fin the ???????of X-281, you ......
So it would help if we knew what we were looking for. Another example, last line:
What is the ?????of X-281?
To fin the ???????of X-281, you ......
So it would help if we knew what we were looking for. Another example, last line:
What is the ?????of X-281?
Answered by
help!
A new potential heart medicine, code-named X-281, is being tested by a pharmaceutical company, Pharma-pill. As a research technician at Pharma-pill, you are told that X-281 is a monoprotic weak acid, but because of security concerns, the actual chemical formula must remain top secret. The company is interested in the drug's Ka value because only the dissociated form of the chemical is active in preventing cholesterol buildup in arteries.
To find the pKa value of X-281, you prepare a 0.079M test solution of X-281. The pH of the solution is determined to be 3.00. What is the pKa of X-281?
To find the pKa value of X-281, you prepare a 0.079M test solution of X-281. The pH of the solution is determined to be 3.00. What is the pKa of X-281?
Answered by
DrBob222
HA ==>H^+ + A^-
Ka = (H^+)(A^-)/(HA)
Convert pH of 3.00 to (H^+).
Plug in that value for (H^+) and (A^-) and for (HA) plug in 0.079-(H^+). solve for Ka, then for pKa. Post your work if you get stuck.
Ka = (H^+)(A^-)/(HA)
Convert pH of 3.00 to (H^+).
Plug in that value for (H^+) and (A^-) and for (HA) plug in 0.079-(H^+). solve for Ka, then for pKa. Post your work if you get stuck.
Answered by
xyz
Is the concentration of A^- just 0.079 then?
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