Question
Good afternoon. How would a formula be made for this question? I believe it is arithmetic.
How many rows are in the corner section of a sports complex if the first row has 18 seats and the last row has 51 seats and each successice row has one additional seat?
How many rows are in the corner section of a sports complex if the first row has 18 seats and the last row has 51 seats and each successice row has one additional seat?
Answers
R_scott
r = 51 - 18
Reiny
AS, with a = 18, d = 1, n = ? and term(n) = 51
a+(n-1)d = term(n)
18 + n-1 = 51
n = 51+1-18 = 34
34 rows
a+(n-1)d = term(n)
18 + n-1 = 51
n = 51+1-18 = 34
34 rows