Asked by Bob
What would be the change in energy for an atom when an electron goes from n=6 to n=3?
I'm assuming it would be negative because you would have to lose energy to go down energy levels. Would that be correct?
I'm assuming it would be negative because you would have to lose energy to go down energy levels. Would that be correct?
Answers
Answered by
DrBob222
delta E = 2.180E-18 J*[1/(n1)^2 - 1/(n2)^2]
delta E = 2.180E-18 J*(1/3^2 - 1/6^2)
This is the amount of energy in J that is emitted when an electron moves from the n = 6 to n = 3. By the way this is for a H atom and not just any atom.
delta E = 2.180E-18 J*(1/3^2 - 1/6^2)
This is the amount of energy in J that is emitted when an electron moves from the n = 6 to n = 3. By the way this is for a H atom and not just any atom.
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