Asked by Damien
For the function g(x)=radical 5-x
Find the general formula for the instantaneous velocity using the definition of derivative
Find the general formula for the instantaneous velocity using the definition of derivative
Answers
Answered by
oobleck
you want the limit as h->0 of
(√(5-(x+h)) - √(5-x))/h
= (√(5-(x+h)) - √(5-x))/h * (√(5-(x+h)) + √(5-x))/(√(5-(x+h)) + √(5-x))
= (5-(x+h))-(5-x))/(h(√(5-(x+h)) + √(5-x)))
= -h/h((√(5-(x+h)) + √(5-x)))
= -1/(√(5-(x+h)) + √(5-x))
now take the limit, and you get
-1/((√(5-x) + √(5-x))
= -1/(2√(5-x))
(√(5-(x+h)) - √(5-x))/h
= (√(5-(x+h)) - √(5-x))/h * (√(5-(x+h)) + √(5-x))/(√(5-(x+h)) + √(5-x))
= (5-(x+h))-(5-x))/(h(√(5-(x+h)) + √(5-x)))
= -h/h((√(5-(x+h)) + √(5-x)))
= -1/(√(5-(x+h)) + √(5-x))
now take the limit, and you get
-1/((√(5-x) + √(5-x))
= -1/(2√(5-x))
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