Hot Steel; Cold Ice: A 36.0 g block of ice sits at −50.0 °C under 1.00 atm constant pressure in a perfectly insulated container. A 225 g mass of stainless steel at 125 °C is dropped onto the ice, and the system is closed. When the system reaches thermal equilibrium, ice remains.
What is the value of q_steel? Enter your answer in Celsius using no decimal places?
4 answers
How about sharing the specific heat of ice and that of stainless steel with us?
delta H fus (H2o) = 333 j/g
delta H vap (H2o) = 2260 J/g
Cp (steel) = 0.500 J g^-1°C^-1
S(H2o(s)) = 2.11 J g^-1 °C^-1
S (H2o(f)) =4.18J g^-1 °C^-1
S (H2o(g)) = 2.00 J g^-1 °C^-1
delta H vap (H2o) = 2260 J/g
Cp (steel) = 0.500 J g^-1°C^-1
S(H2o(s)) = 2.11 J g^-1 °C^-1
S (H2o(f)) =4.18J g^-1 °C^-1
S (H2o(g)) = 2.00 J g^-1 °C^-1
Dr. Bob help me :(((
I'm confused with q_steel. I would think q stands for joules of heat but in degrees C?
Clarify the question please.
Clarify the question please.
1 answer