Wouldn't that be order 1.
rate = y = k*(B)^x where x is the order.
if rate is 3y when (B) = 3(B), what must be the value for x? 1, right?
If the concentration of some reactant, B, is tripled, the rate of reaction triples. What is the order of B?
2 answers
if its tripled and factors increases by 9 the order must be 2 because 3^2 is 9. 3^1 would simply produce 3. That is why it is first order.