Asked by Jan
If the concentration of some reactant, B, is tripled, the rate of reaction triples. What is the order of B?
Answers
Answered by
DrBob222
Wouldn't that be order 1.
rate = y = k*(B)^x where x is the order.
if rate is 3y when (B) = 3(B), what must be the value for x? 1, right?
rate = y = k*(B)^x where x is the order.
if rate is 3y when (B) = 3(B), what must be the value for x? 1, right?
Answered by
LaquaviousBrown-Smith
if its tripled and factors increases by 9 the order must be 2 because 3^2 is 9. 3^1 would simply produce 3. That is why it is first order.