Question

A dock worker slides a 65.0 Kg crate at a constant speed 35.5 m across a cement floor with a coefficient of kinetic friction of .633. How much work does friction do on the crate? How much work does the dock worker do on the crate?
friction and the worker do the same amount of work

work = m * g * μ * d = 65.0 * 9.81 *.633 * 35.5 = ? Joules

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