Asked by Alex
Calculate the potential of a platinum electrode immersed in a solution that is 0.1996 M in V(OH)4 ^+ . 0.0789 M in VO^2+ and 0.0800 M in HClO4
Answers
Answered by
DrBob222
I'm a little confused about exactly what you want but I'll guess this.
V(OH)4^+ + e + 2H^+ ==> VO^2+ + 3H2O
E = Eo - 0.0591/1 log[V(OH)4]^+[H^+)^2/[VO]^2[H2O]^3
You will need to look up the Eo value for [V(OH)4]^+ to [VO]^2+
V(OH)4^+ + e + 2H^+ ==> VO^2+ + 3H2O
E = Eo - 0.0591/1 log[V(OH)4]^+[H^+)^2/[VO]^2[H2O]^3
You will need to look up the Eo value for [V(OH)4]^+ to [VO]^2+
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.