Asked by Alex
Calculate the potential of a platinum electrode immersed in a solution that is 0.1996 M in V(OH)4 ^+ . 0.0789 M in VO^2+ and 0.0800 M in HClO4
Answers
Answered by
DrBob222
I'm a little confused about exactly what you want but I'll guess this.
V(OH)4^+ + e + 2H^+ ==> VO^2+ + 3H2O
E = Eo - 0.0591/1 log[V(OH)4]^+[H^+)^2/[VO]^2[H2O]^3
You will need to look up the Eo value for [V(OH)4]^+ to [VO]^2+
V(OH)4^+ + e + 2H^+ ==> VO^2+ + 3H2O
E = Eo - 0.0591/1 log[V(OH)4]^+[H^+)^2/[VO]^2[H2O]^3
You will need to look up the Eo value for [V(OH)4]^+ to [VO]^2+