Asked by bob
Determine the direction angle (in degrees) for each vector:
Make sure you’re using degrees instead of radians.
If you use a decimal approximation, you must be accurate to at least 3 decimal places.
⟨6,−5⟩ has direction angle: θ= 140.194 but it says im wrong.
What I did is tan^-1(-5/6)= -39.80557109
I then add 180 to -39.80557109 and i got 140.194.
Make sure you’re using degrees instead of radians.
If you use a decimal approximation, you must be accurate to at least 3 decimal places.
⟨6,−5⟩ has direction angle: θ= 140.194 but it says im wrong.
What I did is tan^-1(-5/6)= -39.80557109
I then add 180 to -39.80557109 and i got 140.194.
Answers
Answered by
Reiny
Sketch ⟨6,−5⟩ and it will be in the fourth quadrant
angle in standard position is tan^-1 (5/6) = 39.816°
so in quad IV it would be 360-39.81 = <b>320.194°</b>
notice this would be coterminal with your angle of -39.816°
Are you not familiar with the CAST rule?
angle in standard position is tan^-1 (5/6) = 39.816°
so in quad IV it would be 360-39.81 = <b>320.194°</b>
notice this would be coterminal with your angle of -39.816°
Are you not familiar with the CAST rule?
Answered by
henry2,
Tan A = -5/6
A = -39.806o = 39.806o S. of E. = 320.194o CCW from +x-axis.
A = -39.806o = 39.806o S. of E. = 320.194o CCW from +x-axis.
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