A ball is thrown into the air with an initial upward velocity of 46FT/S its height (h) in feet after T seconds is given by the function H = -16t^2 + 46t + 6. After how many seconds will the ball hit the ground?

Question

A ball is thrown into the air with an initial upward velocity of 46FT/S its height (h) in feet after T seconds is given by the function H = -16t^2 + 46t + 6. After how many seconds will the ball hit the ground￼?

A.3
B.4
C.5
D.6

Please I seriously need help I’m super far behind and need to get this done I have no idea what the answer could be I just need help.

oobleck · Answer

it hits the ground when the height is zero, right? So just solve -16t^2 + 46t + 6 = 0 in the usual ways.

A ball is thrown into the air with an initial upward velocity of 46FT/S its height (h) in feet after T seconds is given by the function H = -16t^2 + 46t + 6. After how many seconds will the ball hit the ground￼?

A ball is thrown into the air with an initial upward velocity of 46FT/S its height (h) in feet after T seconds is given by the function H = -16t^2 + 46t + 6. After how many seconds will the ball hit the ground?