The sum of any two sides must be greater than the third side
x + x+3 > 10
2x > 7
x > 3.5
x + 10 > x +3
10>3 , true for all values of x
x+3 + 10 > x
13 > 0 , true for all values of x
so x > 3.5
x + x+3 > 10
2x > 7
x > 3.5
x + 10 > x +3
10>3 , true for all values of x
x+3 + 10 > x
13 > 0 , true for all values of x
so x > 3.5
To find the lowest value of x, we need to determine the minimum possible value that satisfies the triangle inequality theorem.
According to the triangle inequality theorem, the sum of any two sides of a triangle must be greater than the third side. So, in this case, we have:
x + (x + 3) > 10 and x + 3 + 10 > x
Simplifying these inequalities, we get:
2x + 3 > 10 and x + 13 > x
Now, let's solve them one at a time.
For the first inequality:
2x + 3 > 10
2x > 7
x > 3.5
Since x has to be a whole number, the smallest value that satisfies this inequality is x = 4.
Now, for the second inequality:
x + 13 > x
This inequality does not depend on the value of x. No matter what value of x we choose, this inequality will always be true. So, it doesn't affect our solution.
Therefore, the lowest value of x that satisfies the triangle inequality theorem is x = 4.
In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side. Applying this rule to our given values:
x + (x + 3) > 10 (sum of the first two sides is greater than the third side)
2x + 3 > 10
2x > 7
x > 7/2
Since x is a whole number, the smallest value x can take is 4. Therefore, the lowest value of x is 4 cm.