Asked by Lindsey

if the coefficient of static friction between a 55 kg box and the floor is 0.67 with what minimum horizontal force must it be pulled to get the to crate move
Answered by R_scott
m * g * μ = 55 kg * 9.8 m/s^2 * 0.67 ... Newtons
Answered by henry2,
M*g = 55*9.8 = 539 N.
Fs = u*Fn = 0.67 * 539 = 361 N. = Force of static friction.
F-Fs = M*a.
F - 361 = M*0
F = 361 N.
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