Asked by Apryl

A shot put is thrown upward with a velocity of 35 ft./sec/ at a height of 4 ft. and an angle of 40 degrees. How long will it take for the shot put to be a horizontal distance of 40 ft. from the person throwing it? Acceleration due to gravity is 32 ft./s^2. Round your answer to the nearest hundredth.
Answered by henry2,
Vo = 35Ft./s[40o]
Xo = 35*cos40 = 26.8 m/s.
d = Xo*T = 40
26.8*T = 40
T =
Answered by Apryl
Is the answer 1.49?
Answered by henry2,
Yes.
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