Asked by peter
An impure sample of Na2SO4 weighed 1.562g. A BaSO4 precipitate from this sample weighed 2.496g. Calculate the percentage of sulfur and the percentage purity of salt.
Answers
Answered by
DrBob222
I assume you want % S IN THE SAMPLE.
a m = atomic mass; m m = molar mass
grams S = 2.496 g BaSO4 x (a m S/m m BaSO4) = 2.496 x (32.06/233.34) = ?
Then %S in the unknown = 100(g S/1.562) = ?
% purity = 100*(mass Na2SO4/mass sample) where mass Na2SO4 is
mass BaSO4 ppt x (m m Na2SO4/m m BaSO4)
Post your work if you get stuck.
a m = atomic mass; m m = molar mass
grams S = 2.496 g BaSO4 x (a m S/m m BaSO4) = 2.496 x (32.06/233.34) = ?
Then %S in the unknown = 100(g S/1.562) = ?
% purity = 100*(mass Na2SO4/mass sample) where mass Na2SO4 is
mass BaSO4 ppt x (m m Na2SO4/m m BaSO4)
Post your work if you get stuck.
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