Asked by yep
Carmen is dividing her rectangular garden with a diagonal fence. The length of the garden is 11 feet and the diagonal is 19 feet. Which equation can be used to find the width of the garden? How wide is the garden? Select two answers.
A.11^2+w^2=19^2
B.19−11=w
C.width = 8 feet
D.width = 15.5 feet
A.11^2+w^2=19^2
B.19−11=w
C.width = 8 feet
D.width = 15.5 feet
Answers
Answered by
oobleck
clearly A, from the Pythagorean Theorem.
Now just solve for w.
Now just solve for w.
Answered by
Kenny
Clearly the first
A.11^2+w^2=19^2
Reason be is that with the diagonal crossing the rectangular garden
It immediately forms a right angle triangle
Which give rises to the Pythagoras theorem
11²+w²=19²
W²=19²-11²
W=√(19²-11²)
A.11^2+w^2=19^2
Reason be is that with the diagonal crossing the rectangular garden
It immediately forms a right angle triangle
Which give rises to the Pythagoras theorem
11²+w²=19²
W²=19²-11²
W=√(19²-11²)
Answered by
Beavis
A and D I did the math 11 squared is 121 and 19 squared is 361 so I subtracted 121 from 361 and got 240 and 15.5 times 15.5 equals 240 so it's 15.5 hope this helps
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