Asked by christopher

Solve the equation 2x^2+15x+38=x^2 to the nearest tenth.
Answered by Kenny
x²+15x+38=0

x=(-15±√(225-152)/2

x=(-15±√73)/2

Answered by R_scott
2x^2+15x+38=x^2

subtracting x^2 ... x^2 + 15x + 38 = 0

use the quadratic formula to find the two solutions
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