Solve the equation 2x^2+15x+38=x^2 to the nearest tenth.

Answer 1

x²+15x+38=0

x=(-15±√(225-152)/2

x=(-15±√73)/2

Answer 2

2x^2+15x+38=x^2

subtracting x^2 ... x^2 + 15x + 38 = 0

use the quadratic formula to find the two solutions