Asked by Anonymous
Find the volume of the solid generated by revolving the region bounded by the given curves about the x-axis.
y=x^2+1
x+y=3
Please help me set up the integral!
y=x^2+1
x+y=3
Please help me set up the integral!
Answers
Answered by
Reiny
First you need their intersection, that should be easy
Hope you get (-2,5) and (1,2)
The outer radius is (3-x)
the inner radius is (x^2+1)
so you want ∫ ( (3-x)^2 - (x^2+1)^2 )dx from x = -2 to 1
expand and the rest is pretty straightforward.
Let me know what you get
Hope you get (-2,5) and (1,2)
The outer radius is (3-x)
the inner radius is (x^2+1)
so you want ∫ ( (3-x)^2 - (x^2+1)^2 )dx from x = -2 to 1
expand and the rest is pretty straightforward.
Let me know what you get
Answered by
Anonymous
Awesome, that's what I got!
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