Asked by sassycoco
Stefan is bicycling on a bike trail at an average of 10 mph. Erik starts bicycling on the same trail 30 minutes later at 16 mph. How long will it take Erik to pass Stefan?
Answers
Answered by
Reiny
When Eric passes Stefan, they both will have gone the same distance
since d = rate x time
10t = 30(t - 1/2)
10t= 30t - 15
t = 3/4 hr or 45 minutes
but Eric only traveled for t-1/2 hours = 45-30 minutes or 15 minutes
check:
Stefan went 3/4 hrs at 10 mph = 30/4 miles
Eric went 1/4 hrs at 30 mph = 30/h miles
my answer is correct
since d = rate x time
10t = 30(t - 1/2)
10t= 30t - 15
t = 3/4 hr or 45 minutes
but Eric only traveled for t-1/2 hours = 45-30 minutes or 15 minutes
check:
Stefan went 3/4 hrs at 10 mph = 30/4 miles
Eric went 1/4 hrs at 30 mph = 30/h miles
my answer is correct
Answered by
R_scott
Stefan has a 5 mi head start ... 10 mph * 30 min
Erik catches up at the rate of 6 mph ... 16 mph - 10 mph
time to catch up (pass) ... 5 mi / 6 mph
Erik catches up at the rate of 6 mph ... 16 mph - 10 mph
time to catch up (pass) ... 5 mi / 6 mph
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