Asked by Anonymous

How much heat is needed to bring 120 g of water from 33C to 45C

5 years ago

Answered by Anonymous

q=mc∆t=(120g)(4.186 J/g•C°)(45C-35C)

5 years ago

Answered by Anonymous

q=mc∆t=(120g)(4.186 J/g•C°)(45C-33C)

Typo 33 not 35

5 years ago

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