Asked by Anonymous
A diamond (n = 2.42) immersed in glycerin (n = 1.473) liquid. What is the critical angle at the boundary between diamond and glycerin?
Answers
Answered by
bobpursley
It is not clear to me where the light is coming from, internal to the diamond trying to exit, or light in the glycerine trying to enter the diamond.
angle is arc sin (n<sub>2</sub> / n<sub>1</sub>) where n<sub>1</sub> is the incident ray, and <sub>2</sub> is the refracted ray
arcsin(1.473/2.42)=37.5 degrees (for light in the diamond trying to escape)
angle is arc sin (n<sub>2</sub> / n<sub>1</sub>) where n<sub>1</sub> is the incident ray, and <sub>2</sub> is the refracted ray
arcsin(1.473/2.42)=37.5 degrees (for light in the diamond trying to escape)
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