Asked by Anonymous

Based on the titration results, what is the concentration of the sulfuric acid?

Volume of 𝐾𝑂𝐻 36 mL
Concentration of 𝐾𝑂𝐻 0.16 M
Volume of 𝐻2𝑆𝑂4 12 mL
Answered by DrBob222
H2SO4 + 2KOH ==> K2SO4 + 2H2O
mols KOH = M x L = ?
Look at the equation to see that mols H2SO4 = 1/2 mols KOH
Then M H2SO4 = mols/L
Post your work if you get stuck.
Answered by Anonymous
Hsb
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