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Calculate the pH that results when the following solutions are mixed
1. 35 mL of 0.20 M formic acid π»πΆπππ», πΎπ = 1.77 Γ 10β4
2. 55 mL of 0.10 M sodium formate π»πΆππππ
3. 110 mL of water
1. 35 mL of 0.20 M formic acid π»πΆπππ», πΎπ = 1.77 Γ 10β4
2. 55 mL of 0.10 M sodium formate π»πΆππππ
3. 110 mL of water
Answers
Answered by
DrBob222
Use the HH equation.
1. 35 mL of 0.20 M formic acid π»πΆπππ», πΎπ = 1.77 Γ 10β4
2. 55 mL of 0.10 M sodium formate π»πΆππππ
3. 110 mL of water
Total volume is 200 mL.
(HCOOH) = 0.20 M x (35/200) = ?
(HCOONa) = 0.10 M x (55/200).
Convert Ka to pKa.Substitute into the HH equation. Solve for pH.
Note that HCOOH is the acid and HCOONa is the base.
Post your work if you get stuck.
1. 35 mL of 0.20 M formic acid π»πΆπππ», πΎπ = 1.77 Γ 10β4
2. 55 mL of 0.10 M sodium formate π»πΆππππ
3. 110 mL of water
Total volume is 200 mL.
(HCOOH) = 0.20 M x (35/200) = ?
(HCOONa) = 0.10 M x (55/200).
Convert Ka to pKa.Substitute into the HH equation. Solve for pH.
Note that HCOOH is the acid and HCOONa is the base.
Post your work if you get stuck.
Answered by
Var
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Answered by
Hiral
Calculate the pH that results when the following solutions are mixed
1. 35 mL of 0.20 M formic acid π»πΆπππ», πΎπ = 1.77 Γ 10β4
2. 55 mL of 0.10 M sodium formate π»πΆππππ
3. 110 mL of water
1. 35 mL of 0.20 M formic acid π»πΆπππ», πΎπ = 1.77 Γ 10β4
2. 55 mL of 0.10 M sodium formate π»πΆππππ
3. 110 mL of water