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                Calculate the pH that results when the following solutions are mixed
1. 35 mL of 0.20 M formic acid π»πΆπππ», πΎπ = 1.77 Γ 10β4
2. 55 mL of 0.10 M sodium formate π»πΆππππ
3. 110 mL of water
            
            
        1. 35 mL of 0.20 M formic acid π»πΆπππ», πΎπ = 1.77 Γ 10β4
2. 55 mL of 0.10 M sodium formate π»πΆππππ
3. 110 mL of water
Answers
                    Answered by
            DrBob222
            
    Use the HH equation.
1. 35 mL of 0.20 M formic acid π»πΆπππ», πΎπ = 1.77 Γ 10β4
2. 55 mL of 0.10 M sodium formate π»πΆππππ
3. 110 mL of water
Total volume is 200 mL.
(HCOOH) = 0.20 M x (35/200) = ?
(HCOONa) = 0.10 M x (55/200).
Convert Ka to pKa.Substitute into the HH equation. Solve for pH.
Note that HCOOH is the acid and HCOONa is the base.
Post your work if you get stuck.
    
1. 35 mL of 0.20 M formic acid π»πΆπππ», πΎπ = 1.77 Γ 10β4
2. 55 mL of 0.10 M sodium formate π»πΆππππ
3. 110 mL of water
Total volume is 200 mL.
(HCOOH) = 0.20 M x (35/200) = ?
(HCOONa) = 0.10 M x (55/200).
Convert Ka to pKa.Substitute into the HH equation. Solve for pH.
Note that HCOOH is the acid and HCOONa is the base.
Post your work if you get stuck.
                    Answered by
            Var
            
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                    Answered by
            Hiral
            
    Calculate the pH that results when the following solutions are mixed
1. 35 mL of 0.20 M formic acid π»πΆπππ», πΎπ = 1.77 Γ 10β4
2. 55 mL of 0.10 M sodium formate π»πΆππππ
3. 110 mL of water
    
1. 35 mL of 0.20 M formic acid π»πΆπππ», πΎπ = 1.77 Γ 10β4
2. 55 mL of 0.10 M sodium formate π»πΆππππ
3. 110 mL of water
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