Asked by Brian
Consider 57.5 mL of a solution of weak acid HA (Ka = 1.00 10-6), which has a pH of 3.800. What volume of water must be added to make the pH = 6.000?
Answers
Answered by
DrBob222
Change pH to (H^+).
Write Ka expression.
Plug in (H^+) and (A^-) and solve for (HA).
Then change pH 6.00 to (H^+). Write Ka expression, plug in (H^+), (A^-) and solve for new (HA). Then calculate how much water must be added to convert concn from 3.80 material to concn you want at 6.00 concn.
Write Ka expression.
Plug in (H^+) and (A^-) and solve for (HA).
Then change pH 6.00 to (H^+). Write Ka expression, plug in (H^+), (A^-) and solve for new (HA). Then calculate how much water must be added to convert concn from 3.80 material to concn you want at 6.00 concn.
Answered by
brian.
how do u calc how much water is needed?
Answered by
DrBob222
Molarity*liters of 1 soln = molarity*liters of other solution.
Answered by
Brian
for the second set i put Ph=6 and got H+=1e-6 and then HA=1e6
i think that's wrong.. whats wrong with it?
i think that's wrong.. whats wrong with it?
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