Asked by OCA please help me
A rectangular box has a length of 12 inches and a width of 4 inches. The length of the three-dimensional diagonal of the box is 14 inches. What is the height of the box? Show all of your work.
Im confused should i divide? or what should i do to find the answer? and what is the answer??
Please help! thanks!
Im confused should i divide? or what should i do to find the answer? and what is the answer??
Please help! thanks!
Answers
Answered by
oobleck
12^2 + 4^2 + h^2 = 14^2
Answered by
Reiny
Did you make a sketch?
if you have a box with dimensions x by y by z
then the length of the diagonal is √(x^2 + y^2 + z^2) , that should be easy to see
so you have √(12^2 + 4^2 + h^2) = 14
square both sides:
144 + 16 + h^2 = 196
take over
if you have a box with dimensions x by y by z
then the length of the diagonal is √(x^2 + y^2 + z^2) , that should be easy to see
so you have √(12^2 + 4^2 + h^2) = 14
square both sides:
144 + 16 + h^2 = 196
take over
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