Asked by Koffi
A series arrangement of three capacitors of value 8μF, 12μF, 24μF is connected in series with a 90-V battery.
(i) Draw an open circuit diagram for
this arrangement.
(ii) Calculate the effective
capacitancee in the circuit.
(iii) On close circuit, calculate the
charge on each capacitor when
fully charged.
(iv) Determine the pd across the
8μF capacitor.
(i) Draw an open circuit diagram for
this arrangement.
(ii) Calculate the effective
capacitancee in the circuit.
(iii) On close circuit, calculate the
charge on each capacitor when
fully charged.
(iv) Determine the pd across the
8μF capacitor.
Answers
Answered by
henry2,
2. 1/C = 1/C1+1/C2+1/C3 = 1/8+1/12+1/24 = 3/24+2/24+1/24 = 6/24
C = 4 uF.
3. Q = CE = 4 * 90 = 360 uC = 3.6*10^-4 coulombs = Q1 = Q2 = Q3.
Series capacitors have same charge.
4. Q = C1*V1 = 360
8V1 = 360
V1 = 45 volts.
C = 4 uF.
3. Q = CE = 4 * 90 = 360 uC = 3.6*10^-4 coulombs = Q1 = Q2 = Q3.
Series capacitors have same charge.
4. Q = C1*V1 = 360
8V1 = 360
V1 = 45 volts.
Answered by
Issahaka
Thanks
Answered by
Blessing
Quite a huge help
Thanks alot
Thanks alot
Answered by
Rema
Good keep it up
Answered by
Daniella
thank you very much
Answered by
Jhoseph
Thanks alot
God bless
God bless
Answered by
Physics
Draw an open circuit diagram for this arrangement
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