q = mass Cu x specific heat Cu x (Tfinal-Tinitial)
-1458.4 = 47.5 x 0.39 x (Tfinal - 99)
Solve for Tfinal.
Starting with a 47.5 piece of copper at 99 oC, you remove 1458.4 J of heat. What is the new temperature of the copper? specific heat of copper = 0.39 J/g oC
1 answer
1 answer