Question
What is the perimeter of the rectangle if the length is (x2 + 5x - 4) and the width is (3x - 1)?
A. -1
B. -2
C. -3
D. -4
E. -5
F. -6
A. -1
B. -2
C. -3
D. -4
E. -5
F. -6
Answers
Reiny
P = 2L + 2W
= 2(x^2 + 5x - 4) + 2(3x - 1)
= 2x^2 + 10x - 8 + 6x - 2
= 2x^2 + 16x - 10
Your answer choices makes no sense, they are all negative integers.
A perimeter cannot be negative.
Did you mismatch answers with another question?
= 2(x^2 + 5x - 4) + 2(3x - 1)
= 2x^2 + 10x - 8 + 6x - 2
= 2x^2 + 16x - 10
Your answer choices makes no sense, they are all negative integers.
A perimeter cannot be negative.
Did you mismatch answers with another question?