molality = m = mols solute/kg solvent
a 3.5 wt% NaCl is 3.5 g NaCl/100 g solution and that is
3.5 g NaCl/(3.5 g NaCl + 96.5 g H2O) So if we take a 1000 g sample it will contain 35 g NaCl in 965 g H2O.
m = mols NaCl/kg solvent.
mols NaCl = g NaCl/molar mass NaCl = 35/58.5 = ?
kg solvent = 0.965
Solve for m = ?
assuming that sea water hos 3.5 weight percent in aqueous solution of NaCl what is molality
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