Asked by stefani

What is the osmotic pressure (in atm) when 69.7 g of a solute (MW = 2790 g/mol) is dissolved in 1.00 L of a solution at 20 °C?

Answers

Answered by DrBob222
pi = nRT
You can calculate n, you know R, plug in T in kelvin, solve for pi in atm if you use R as 0.08206
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