Asked by Ibra
ten identical PCs are in the inventory of a dealer,one has a hidden defect.if 3 are to be shipped,and the computers are selected in such a way that each has the same probability of being shipped,find
I.the number of ways in which 3 of the 10 PCs can be selected for shipment.
II.the total number of ways in which 3 of the 10PCs can be selected so that the one with the hidden defect will be included for shipment.
III.the probability that the computer with the hidden defect will be shipped.
I.the number of ways in which 3 of the 10 PCs can be selected for shipment.
II.the total number of ways in which 3 of the 10PCs can be selected so that the one with the hidden defect will be included for shipment.
III.the probability that the computer with the hidden defect will be shipped.
Answers
Answered by
R_scott
I. 3C10
II. 3C10 - 3C9
III. II / I
II. 3C10 - 3C9
III. II / I
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