Asked by Mason

A 20 kg block rests on a rough horizontal table. A rope is attached to the block and is pulled with a force of 80 N to the left. As a result, the block accelerates at 2.5 m/s2. The coefficient of kinetic friction μk between the block and the table is ___ .( Round the answer to the nearest hundredth.)
This is big boi stuff!
Answered by R_scott
20 kg * 2.5 m/s^2 = 50 N

so the frictional force is ... 80 N - 50 N = 30 N

Ff = m * g * μk

μk = 30 N / (20 kg * 9.8 m/s^2) = 30 N / 196 N


the coefficient of friction is just a number ... no units
Answered by Mason
What is the answer rounded to the nearest hundred?
Answered by R_scott
calculator broken??
Answered by Alexander
Typically people would get numeric values for these types of questions. If you were to do the math on the calculator correctly you should get Syntax Error. It seems odd but i put that on all my tests and my teachers call my parents to let them know how good i am doing
Answered by Box Jellyfish
Frictional force after calculation = 30N
Coefficient of friction = 0.15
Answered by Spade
0.15
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