Asked by chemnerd
A solution of naphthalene (C10H8, 128.17 g/mol) in benzene (C6H6, 78.11g/mol) has a freezing point temperature of 3.41 C. Calculate the mass percent (%m/m) of naphthalene in this solution and the boiling point of the solution.
Benzene
Kf: 5.12 C/m
Kb: 2.53 C/m
Tf: 5.53 C
Tb: 80.10 C
Density: 0.876 g/cm^3
Benzene
Kf: 5.12 C/m
Kb: 2.53 C/m
Tf: 5.53 C
Tb: 80.10 C
Density: 0.876 g/cm^3
Answers
Answered by
DrBob222
dTfreezing = 5.53-3.41 = Kf*m. You know Kf and dT, solve for molality.
Then using the same m, plug that into dTboiling = Kb*m. Knowing Kb and m, you can calculate delta T. Add delta T to the normal boiling point to find the new b.p.
I don't see information to calculate grams either solvent or solute.
The density you list is the density of what?
Then using the same m, plug that into dTboiling = Kb*m. Knowing Kb and m, you can calculate delta T. Add delta T to the normal boiling point to find the new b.p.
I don't see information to calculate grams either solvent or solute.
The density you list is the density of what?
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