Asked by Hi

X^2-18x+81=0
Answered by Hi
Can someone please help?!?!?!?
Answered by oobleck
note that 81 = 9^2 and 18 = 2*9
That means you have a perfect square:
(x-9)^2 = 0
So the roots are ...
Answered by Hi
So it would be
(X-9) (x+9)?
Answered by Hi
So then x=9
Answered by henry2,
x^2-18x+81 = 0. 81 = -9*-9. (-9)+(-9) = -18 - B.
(x-9)(x-9) = 0
x-9 = 0, X = 9.
Only one solution.
Answered by Hi
Thank you!!
Answered by henry2,
You are welcome.
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