Asked by Nancy drew
Suppose that 30% of a population carries a certain gene. You want to estimate the probability that it will take at least a sample of four to find a person that carries the gene, how could you simulate a person having or not having the gene?
A) 0, 1, 2 could represent a person that carries the gene, and 3, 4, 5, 6, 7, 8, 9 could represent a person that does not carry the gene.
B) 0, 1, 2, 3 could represent a person that carries the gene, and 4, 5, 6, 7, 8, 9 could represent a person that does not carry the gene.
C) 0, 1, 2 could represent a person that does not carry the gene, and 3, 4, 5, 6, 7, 8, 9 could represent a person that carries the gene.
D) 0, 1, 2, 3 could represent a person that does not carry the gene, and 4, 5, 6, 7, 8, 9 could represent a person that carries the gene.
A) 0, 1, 2 could represent a person that carries the gene, and 3, 4, 5, 6, 7, 8, 9 could represent a person that does not carry the gene.
B) 0, 1, 2, 3 could represent a person that carries the gene, and 4, 5, 6, 7, 8, 9 could represent a person that does not carry the gene.
C) 0, 1, 2 could represent a person that does not carry the gene, and 3, 4, 5, 6, 7, 8, 9 could represent a person that carries the gene.
D) 0, 1, 2, 3 could represent a person that does not carry the gene, and 4, 5, 6, 7, 8, 9 could represent a person that carries the gene.
Answers
Answered by
oobleck
sure looks like A to me. 3/10 success rate
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