Asked by Jessica
A jet engine applies a force of 300 N horizontally to the right against a 50 kg rocket. The force of air friction 200 N. If the rocket is thrust horizontally 2.0 m, what is the kinetic energy gained by the rocket.
Answers
Answered by
bobpursley
KE gained=energy initial-frictionloss=300N*2m - 100*2=400 J
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