Calculus? consider the derivative of s wrespect to time, that is vertical velocity, and at max altitude, vertical velocity is zero.
ds/dt=0=-9.8 t+ 24.5 solve for t.
Geometry Method. this is a parabola, s=0 initially, and at the end. Take thequadratic, solve for t when s=0, you get both values (initial and final). at t/2 is the time of max altitude.
A science project studying catapults sent a projectile into the air with an initial velocity of 24.5 m/s. The formula for distance (s) in meters with respect to time in seconds is
s = -4.9t2 + 24.5t.
Find the time that this projectile would appear to have the maximum distance above the ground.
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