Solve: 48+2x^2=16

Answer 1

I think I saw this same question yesterday.

If as written:
48 + 2x^2 = 16
2x^2 = -32
x^2 = -16
x = ± 4i , where i = √-1

If you meant:
48x + 2x^2 = 16
x^2 + 24x - 8 = 0
x + (-24 ± √608)/2

If you meant:
.....

Answer 2

Hello. It is the first one.

I get up to x^2= -16, but how does x = ± 4i work? I assume it's opposite of ^ in this case to remove ^2. What is ± in this case?