Asked by Anonymous
Solve the equations:
48+2x^2=16
k^2 = k
17^2 = 15^2+(2m)^2
48+2x^2=16
k^2 = k
17^2 = 15^2+(2m)^2
Answers
Answered by
Isaac
48+2x²=16
Reduce by 2
24+x²=8
x²=-16
x=✓(-16)
You would have to go imaginary now
Assume j²=-1
X=✓(j²16)
x=±4j
------------
k²=k
(k²-k)=0
K(k-1)=0
K=0 or k=1
---------
2m²=17²-15²
2m²=(17+15)(17-15)
2m²=32×2
M²=16×2
m=√(16×2)
M=±4√2
Please see if you can help me up there in my probability thanks
Reduce by 2
24+x²=8
x²=-16
x=✓(-16)
You would have to go imaginary now
Assume j²=-1
X=✓(j²16)
x=±4j
------------
k²=k
(k²-k)=0
K(k-1)=0
K=0 or k=1
---------
2m²=17²-15²
2m²=(17+15)(17-15)
2m²=32×2
M²=16×2
m=√(16×2)
M=±4√2
Please see if you can help me up there in my probability thanks