Asked by Anonymous
Solve the equations:
48+2x^2=16
k^2 = k
17^2 = 15^2+(2m)^2
48+2x^2=16
k^2 = k
17^2 = 15^2+(2m)^2
Answers
Answered by
Isaac
48+2x²=16
Reduce by 2
24+x²=8
x²=-16
x=✓(-16)
You would have to go imaginary now
Assume j²=-1
X=✓(j²16)
x=±4j
------------
k²=k
(k²-k)=0
K(k-1)=0
K=0 or k=1
---------
2m²=17²-15²
2m²=(17+15)(17-15)
2m²=32×2
M²=16×2
m=√(16×2)
M=±4√2
Please see if you can help me up there in my probability thanks
Reduce by 2
24+x²=8
x²=-16
x=✓(-16)
You would have to go imaginary now
Assume j²=-1
X=✓(j²16)
x=±4j
------------
k²=k
(k²-k)=0
K(k-1)=0
K=0 or k=1
---------
2m²=17²-15²
2m²=(17+15)(17-15)
2m²=32×2
M²=16×2
m=√(16×2)
M=±4√2
Please see if you can help me up there in my probability thanks
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.