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Use triangle ABC to write the value of sinB as a ratio.
Triangle A B C with right angle at A, and hypotenuse B C. The following measures are labeled in the figure: A B=5, B C=13, A C=12.



What is the ratio for sinB?
Enter your answer as a fraction in simplest form, like this: 42/53

5 years ago

Answers

henry2,
sinB = AC/BC =
5 years ago
Bruh
Answer?
4 years ago
Bruh
Unless you're saying it's 12/13
4 years ago
Bruh
Yeah the answer is 12/13
4 years ago

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