Asked by GROOVE

Use triangle ABC to write the value of sinB as a ratio.
Triangle A B C with right angle at A, and hypotenuse B C. The following measures are labeled in the figure: A B=5, B C=13, A C=12.



What is the ratio for sinB?
Enter your answer as a fraction in simplest form, like this: 42/53

Answers

Answered by henry2,
sinB = AC/BC =
Answered by Bruh
Answer?
Answered by Bruh
Unless you're saying it's 12/13
Answered by Bruh
Yeah the answer is 12/13
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