Asked by Ann
how should I integrate 1/(x^2 +1)^5
Answers
Answered by
drwls
According to my table of integrals, this one is a real mess.
I had to use a recursion relation. This is equivalent to using integration by parts several times. The first step yields
INT of 1/(x^2 +1)^5
= x/[8(x^2+1)^4]
+ (1/4) INT of 1/(x^2 +1)^4
In the next step you reduce the second integral to another function of x plus the integral of 1/(x^2 +1)^3 etc.
There will be a log or hyperbolic tangent term in the last step
I had to use a recursion relation. This is equivalent to using integration by parts several times. The first step yields
INT of 1/(x^2 +1)^5
= x/[8(x^2+1)^4]
+ (1/4) INT of 1/(x^2 +1)^4
In the next step you reduce the second integral to another function of x plus the integral of 1/(x^2 +1)^3 etc.
There will be a log or hyperbolic tangent term in the last step
Answered by
Ann
Drwls, how did you derive the first step so that I can continue with the remainder of the steps?
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