Asked by Mea
A system exhibits simple harmonic motion with a frequency of 0.85 cycles per second. Calculate the acceleration experienced by the mass 3.0 m from the equilibrium point.
Answers
Answered by
oobleck
you know that sin(kt) has period 2π/k, so its frequency is k/2π
So, you need to find k such that k/2π = 0.85
Then just take the 2nd derivative of that to find the acceleration.
the 2nd derivative of sin(kx) is just -k^2 sin(kx)
So, you need to find k such that k/2π = 0.85
Then just take the 2nd derivative of that to find the acceleration.
the 2nd derivative of sin(kx) is just -k^2 sin(kx)
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