Question

Y=X2+bx+c (the 2 means squared)

Y = 16 when x= 0
Y= 0 when x=-2

Find the values of b & c

Answer 1

set up two equations and solve

the 1st one is a gift ... 16 = 0^2 + (b * 0) + c ... 16 = c

0 = (-2)^2 + (-2 b) + 16