unless this is a trick question,
PE = mgh
as usual, right?
PE = mgh
as usual, right?
Gravitational potential energy is given by the formula:
Potential Energy = mass * g * height
where:
mass = 5 kg (mass of the shot)
g = 9.8 m/s^2 (acceleration due to gravity)
height = 3 m (initial height of the shot)
Substituting these values into the formula, we can calculate the potential energy:
Potential Energy = 5 kg * 9.8 m/s^2 * 3 m
Potential Energy = 147 J
Therefore, the potential energy of the shot as it left the hand relative to the ground was 147 Joules.
Potential Energy = mass × gravity × height
Given:
Mass of the shot (m) = 5 kg
Height when released (h1) = 3 m (above ground)
Maximum height (h2) = 14.5 m (above ground)
Gravity (g) = 9.8 m/s² (acceleration due to gravity)
First, let's calculate the potential energy when the shot was released:
Potential Energy1 = mass × gravity × height1
Potential Energy1 = 5 kg × 9.8 m/s² × 3 m
Potential Energy1 = 147 joules
Now, let's calculate the potential energy at the maximum height:
Potential Energy2 = mass × gravity × height2
Potential Energy2 = 5 kg × 9.8 m/s² × 14.5 m
Potential Energy2 = 713.5 joules
Since potential energy is dependent on an object's position, the potential energy at the maximum height is the maximum potential energy reached by the shot.
Therefore, the potential energy of the shot as it left the hand relative to the ground is 147 joules.