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Graph the quadratic functions y = -2x2 and y = -2x2 + 4 on a separate piece of paper. Using those graphs, compare and contrast...Asked by henry2,
Graph the quadratic functions y = -2x^2 and y = -2x^2 + 4 on a separate piece of paper. Using those graphs, compare and contrast the shape and position of the graphs.
Answers
Answered by
Reiny
I would suggest you graph the two functions on the same grid, not on separate pieces of paper.
You will be able to answer the questions so much easier.
Make a table of values for each one, I suggest you use the same values of x for each one.
You will be able to answer the questions so much easier.
Make a table of values for each one, I suggest you use the same values of x for each one.
Answered by
oobleck
there are many handy online graphing sites that you can use.
Answered by
Anonymous
you guys aren't helping
Answered by
Anonymouse
Don't be rude.
It's really easy to graph things online, and in case you haven't noticed, you can't send images on Jishka.
Maybe try putting effort into your work for once, and be grateful that someone tried helping you.
It's really easy to graph things online, and in case you haven't noticed, you can't send images on Jishka.
Maybe try putting effort into your work for once, and be grateful that someone tried helping you.
Answered by
lol
learn how to spell first anonymouse
Answered by
Mori <3
Hey, let's calm here. I know, stressing about school sucks and I did the same as all of you- Luckily, I graphed it on Desmos (which you can always use if youre stuck on a graph question, its a site online!!) and here's the answer i got:
PARAPHRASE THE FOLLOWING:
The first equation has a vertex at (0, 0). Adding 4 to the end of the equation causes the y value to do the same, moving the vertex up by 4. This means the vertex is now at (0, 4). This changes all known points on the function, as they will all be slightly positioned around the first function.
PARAPHRASE THE FOLLOWING:
The first equation has a vertex at (0, 0). Adding 4 to the end of the equation causes the y value to do the same, moving the vertex up by 4. This means the vertex is now at (0, 4). This changes all known points on the function, as they will all be slightly positioned around the first function.
Answered by
meow
thanks soooo much every1!! :3
Answered by
CAY
Thank you @Mori<3
Answered by
wanna die
thx